Jimmy Kimmel, the host of "Jimmy Kimmel Live!", has posted a hilarious selfie on his Twitter account featuring the Clinton family, reports NYDailyNews. The picture, posted after he interviewed members of the former first family during a forum, was a humorous dig at the famous Ellen DeGeneres selfie during the 2014 Oscars.
Posted over 17 hours ago at the time of writing this, the tweet has "only" managed over 6000 Retweets and over 7000 favorites - a far cry from Ellen's record breaking 3.3 million plus retweets. In the tweet, Jimmy Kimmel has actually tagged Ellen and told her that his selfie doesn't have a Brad Cooper - but does contain "3 Clintons & a Kimmel".
.@TheEllenShow- No Brad Cooper but 3 Clintons & a Kimmel @BillClinton @HillaryClinton @ChelseaClinton #selfie pic.twitter.com/GyGFxnUjfPJimmy Kimmel hosted the interview in front of a crowd of over 1,000 students at the Clinton Global Initiative University in Tempe, Arizona, according to Time. The interview covered various topics pertaining to the Clintons including how the couple met at Yale Law School. There were a few policy related questions as well. The most important question the answer to which everyone was looking forward to was whether Hillary Clinton had made up her mind to run for President in 2016.
— Jimmy Kimmel (@jimmykimmel) March 23, 2014
Jimmy did ask her the question eventually to which she gave a very straight forward answer. She said she hadn't yet decided, while adding, "I am very much concerned about the direction of our country. And it's not just who runs for office but what they do when they get there and how we bring people together and particularly empower".
This funny Tweet from Jimmy Kimmel comes just days after Ex President Bill Clinton had posed for a photo with two prostitutes at a philanthropy gala held in Los Angeles for Unite4Charity. At the same event, he had also posed with Demi Lovato for another selfie, which was posted to her Instagram Account.
How many retweets do you think will this Jimmy Kimmel selfie eventually generate?