’21 Jump Street’ Sequel Headed To Theaters Next Year
A sequel to the 2012 box office his 21 Jump Street is headed to theaters next year.
The folks at Sony Pictures announced the follow-up at CinemaCon. The studio listed the movie among the title among other flicks currently slated to his cinemas in 2014. However, a specific release date has not been set as of this writing.
Made on a budget of approximately $42 million, 21 Jump Street went on to make a tidy $138 million in the US alone. The film’s foreign box office receipts pushed its international total to an impressive $200 million.
It’s believed that stars Channing Tatum and Jonah Hill will return for the sequel. It’s currently unknown if directors Phil Lord and Chris Miller will jump on-board for the follow-up. Since the pair are currently working on The LEGO Movie, they may not be able to fit another 21 Jump Street movie into their schedule at the moment.
Based on the popular 80s television series, the big screen adaptation followed two cops as they attempt to take down a synthetic drug ring. The mission forces the partners go undercover at a local high school as students. Depending on what you thought of the movie, hilarity is said to have ensued.
Jonah Hill revealed that he is currently working on the script with Michael Bacall. The project is expected to go in front of the camera in September.
It’s not altogether surprising that Sony Pictures is interested in putting together a 21 Jump Street sequel. Given the movie made a ton of cash at the box office, a follow-up seems perfectly logical. Channing Tatum’s popularity no doubt influenced this decision as well.
While Tatum fans are waiting for the follow-up to hit theaters, they can check out the actor’s latest action flick White House Down later this year. The film, which finds a Secret Service agent battling terrorists inside the White House, opens on June 28.
Were you a fan of the big screen version of 21 Jump Street? Are you excited that Sony Pictures intends to release the sequel into theaters next year?
